Evaporation

The volume of water lost to evaporation on a given day is calculated:

$V_{evap}=5*(1-\frac{LAI}{LAI_{evap}})*E_o*SA$ if $LAI<LAI_{evap}$ 8:1.3.5

$V_{evap}=0$ if $LAI \ge LAI_{evap}$ 8:1.3.6

where $V_{evap}$ is the volume of water removed from the water body by evaporation during the day (m$^3$ H$_2$O), $LAI$ is the leaf area index of the plants growing in the pothole, $LAI_{evap}$ is the leaf area index at which no evaporation occurs from the water surface, $E_o$ is the potential evapotranspiration for a given day (mm H$_2$O), and $SA$ is the surface area of the water body (ha).