# Resuspension

Pesticide in the sediment layer is available for resuspension. The amount of pesticide that is removed from the sediment via resuspension is:

        $$pst\_{rsp,wtr}=v\_r*SA*\frac{pst\_{lksed}}{V\_{tot}}$$                                 8:4.2.10

where $$pst\_{rsp,wtr}$$ is the amount of pesticide removed via resuspension (mg pst), $$v\_r$$ is the resuspension velocity (m/day), $$SA$$ is the surface area of the water body (m$$^2$$), $$pst\_{lksed}$$ is the amount of pesticide in the sediment (mg pst), and $$V\_{tot}$$ is the volume of the sediment layer (m$$^3$$). The volume of the sediment layer is calculated:

         $$V\_{tot}=SA\*D\_{sed}$$                                                    8:4.2.11

where $$V\_{tot}$$ is the volume of the sediment layer (m$$^3$$), $$SA$$ is the surface area of the water body (m$$^2$$), $$D\_{sed}$$ is the depth of the active sediment layer (m). Pesticide removed from the sediment layer by resuspension is added to the water layer.