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# Overflow

Pothole outflow caused by overflow is calculated:

      $$V\_{flowout}=V-V\_{pot,mx}$$                         if   $$V >V\_{pot,mx}$$                           8:1.3.10

where $$V\_{flowout}$$ is the volume of water flowing out of the water body during the day   (m$$^3$$ H$$\_2$$O), $$V$$ is the volume of water stored in the pothole (m$$^3$$ H$$*2$$O), and $$V*{pot,mx}$$ is the maximum amount of water that can be stored in the pothole (m$$^3$$ H$$\_2$$O).