# Precipitation

The volume of precipitation falling on the pothole during a given day is calculated:

&#x20;        $$V\_{pcp}=10\*R\_{day}\*SA$$                                                             8:1.3.3

where $$V\_{pcp}$$ is the volume of water added to the water body by precipitation during the day (m$$^3$$ H$$*2$$O), $$R*{day}$$ is the amount of precipitation falling on a given day (mm H$$\_2$$O), and $$SA$$ is the surface area of the water body (ha).


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