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Surface Area

The surface area of the pothole is needed to calculate the amount of precipitation falling on the water body as well as the amount of evaporation and seepage. Surface area varies with change in the volume of water stored in the impoundment. For surface area calculations, the pothole is assumed to be cone-shaped. The surface area is updated daily using the equation:

$SA=\frac{\pi}{10^4}*(\frac{3*V}{\pi *slp})^{2/3}$ 8:1.3.2

where $SA$ is the surface area of the water body (ha), $V$ is the volume of water in the impoundment (m $^3$ H $_2$ O), and $slp$ is the slope of the HRU (m/m).

Surface Area

$SA=\frac{\pi}{10^4}*(\frac{3*V}{\pi *slp})^{2/3}$ 8:1.3.2

where $SA$ is the surface area of the water body (ha), $V$ is the volume of water in the impoundment (m $^3$ H $_2$ O), and $slp$ is the slope of the HRU (m/m).