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Volatilization

Pesticide in the dissolved phase is available for volatilization. The amount of pesticide removed from the water via volatilization is:

pstvol,wtr=vvβˆ—SAβˆ—Fdβˆ—pstlkwtrVpst_{vol,wtr}=v_v*SA*\frac{F_d*pst_{lkwtr}}{V} pstvol,wtr​=vvβ€‹βˆ—SAβˆ—VFdβ€‹βˆ—pstlkwtr​​ 8:4.1.8

where pstvol,wtrpst_{vol,wtr} pstvol,wtr​ is the amount of pesticide removed via volatilization (mg pst), vvv_v vv​ is the volatilization mass-transfer coefficient (m/day), SASA SA is the surface area of the water body (m2^2 2), FdF_d Fd​ is the fraction of total pesticide in the dissolved phase, pstlkwtrpst_{lkwtr} pstlkwtr​ is the amount of pesticide in the water (mg pst), and V is the volume of water in the water body(m3^3 3 H2_2 2​O).

The volatilization mass-transfer coefficient can be calculated based on Whitman’s two-film or two-resistance theory (Whitman, 1923; Lewis and Whitman, 1924 as described in Chapra, 1997). While the main body of the gas and liquid phases are assumed to be well-mixed and homogenous, the two-film theory assumes that a substance moving between the two phases encounters maximum resistance in two laminar boundary layers where transfer is a function of molecular diffusion. In this type of system the transfer coefficient or velocity is:

8:4.1.9

where is the volatilization mass-transfer coefficient (m/day), is the mass-transfer velocity in the liquid laminar layer (m/day), is the mass-transfer velocity in the gaseous laminar layer (m/day), is Henry’s constant (atm m mole), is the universal gas constant (8.206 10 atm m (K mole)), and is the temperature ().

For lakes, the transfer coefficients are estimated using a stagnant film approach:

8:4.1.10

where is the mass-transfer velocity in the liquid laminar layer (m/day), is the mass-transfer velocity in the gaseous laminar layer (m/day), is the liquid molecular diffusion coefficient (m/day), is the gas molecular diffusion coefficient (m/day), is the thickness of the liquid film (m), and is the thickness of the gas film (m).

Alternatively, the transfer coefficients can be estimated with the equations:

8:4.1.11

8:4.1.12

where is the mass-transfer velocity in the liquid laminar layer (m/day), is the mass-transfer velocity in the gaseous laminar layer (m/day), is the oxygen transfer coefficient (m/day), is the molecular weight of the compound, and is the wind speed (m/s). Chapra (1997) lists several different equations that can be used to calculate .

vv=Klβˆ—HeHe+Rβˆ—TKβˆ—(Kl/Kg)v_v=K_l*\frac{H_e}{H_e+R*T_K*(K_l/K_g)} vv​=Klβ€‹βˆ—He​+Rβˆ—TKβ€‹βˆ—(Kl​/Kg​)He​​
vvv_v vv​
KlK_l Kl​
KgK_g Kg​
HeH_{e}He​
3^3 3
βˆ’1^{-1} βˆ’1
RR R
βˆ—* βˆ—
βˆ’5^{-5} βˆ’5
3^33
βˆ’1^{-1}βˆ’1
TKT_K TK​
KK K
Kl=DlzlK_l=\frac{D_l}{z_l} Kl​=zl​Dl​​
Kg=DgzgK_g=\frac{D_g}{z_g} Kg​=zg​Dg​​
KlK_l Kl​
KgK_g Kg​
DlD_l Dl​
2^2 2
DgD_g Dg​
2^2 2
zlz_l zl​
zgz_g zg​
Kl=Kl,O2βˆ—(32MW)0.25K_l=K_{l,O_2}*(\frac{32}{MW})^{0.25} Kl​=Kl,O2β€‹β€‹βˆ—(MW32​)0.25
Kg=168βˆ—ΞΌwβˆ—(18MW)0.25K_g =168*\mu_w*(\frac{18}{MW})^{0.25} Kg​=168βˆ—ΞΌwβ€‹βˆ—(MW18​)0.25
KlK_l Kl​
KgK_g Kg​
Kl,O2K_{l,O_2} Kl,O2​​
MWMW MW
ΞΌw\mu_w ΞΌw​
Kl,O2K_{l,O_2} Kl,O2​​