# Evaporation

The volume of water lost to evaporation on a given day is calculated:

&#x20;         $$V_{evap}=10*\eta*E_o*SA$$                                                           8:1.2.9

where $$V_{evap}$$ is the volume of water removed from the water body by evaporation during the day (m$$^3$$ H$$_2$$O), $$\eta$$ is an evaporation coefficient (0.6), $$E_o$$ is the potential evapotranspiration for a given day (mm H$$_2$$O), and $$SA$$ is the surface area of the water body (ha).
