# Overflow

Pothole outflow caused by overflow is calculated:

&#x20;     $$V_{flowout}=V-V_{pot,mx}$$                         if   $$V >V_{pot,mx}$$                           8:1.3.10

where $$V_{flowout}$$ is the volume of water flowing out of the water body during the day   (m$$^3$$ H$$_2$$O), $$V$$ is the volume of water stored in the pothole (m$$^3$$ H$$_2$$O), and $$V_{pot,mx}$$ is the maximum amount of water that can be stored in the pothole (m$$^3$$ H$$_2$$O).
