# Evaporation

The volume of water lost to evaporation on a given day is calculated:

$$V_{evap}=5*(1-\frac{LAI}{LAI_{evap}})*E_o*SA$$     if    $$LAI<LAI_{evap}$$                8:1.3.5

$$V_{evap}=0$$                                                   if    $$LAI \ge LAI_{evap}$$                8:1.3.6

where $$V_{evap}$$ is the volume of water removed from the water body by evaporation during the day (m$$^3$$ H$$_2$$O), $$LAI$$ is the leaf area index of the plants growing in the pothole, $$LAI_{evap}$$ is the leaf area index at which no evaporation occurs from the water surface, $$E_o$$ is the potential evapotranspiration for a given day (mm H$$_2$$O), and $$SA$$ is the surface area of the water body (ha).
